(Melbourne) The ex-no 1 world Naomi Osaka (current 17e in the WTA rankings) qualified Tuesday in three sets for the second round of the Australian Open.
Crowned in Melbourne in 2019 and 2021, the Japanese won 6-3, 3-6, 6-4 against the Croatian Antonia Ruzic (65e).
The four-time Grand Slam winner will play in the next round against Romanian Sorana Cirstea (41e), who started the last Australian Open of her career at age 35 by eliminating the German Eva Lys (39e).
Entering the court with a white parasol, a wide-brimmed hat and a long white train, Osaka started the match with her feet on the ground to quickly lead 3-0.
Ruzic recovered to 3-3 before again losing three games in a row and the first set.
The Croatian responded in the second round, winning by the same score.
In the decisive set, Osaka broke from the start to break away at 2-0, but Ruzic came back to her level again before taking her throw in to lead 4-3, service to follow.
This time it was the Japanese who held on to get back to 4-4, before inflicting a shutout then a new break on Ruzic to seal her qualification with a final winning backhand, after almost 2 hours 30 minutes of fighting.
Osaka played her first Grand Slam match on Tuesday since her semi-final at the United States Open in September, her best run in a major tournament since she returned to the circuit in early 2024 after the birth of her first child.
