(Auckland) Jakub Mensik, third seed, hammered 18 aces on Saturday and defeated Argentina’s Sebastián Báez 6-3, 7-6 (7) in the final of the Auckland tournament.

The 20-year-old Czech saved three set points in the second set and won a second ATP Tour title.

Mensik, ranked 18e in the world, will now travel to Melbourne for the Australian Open, where he will face Spaniard Pablo Carreno Busta in the first round.

Báez, who defeated American favorite Ben Shelton in the quarter-finals in Auckland, will play Giovanni Mpetshi Perricard in the first round in Melbourne.

PHOTO MICHAEL BRADLEY, AGENCE FRANCE-PRESSE

Sebastián Báez

Mensik won the first set in 31 minutes with 11 aces and found himself serving for the second set at 6-5. However, Báez broke his serve for the first time in the match. He then led 6-3 in the tiebreaker, but Mensik won the next three points.

Then, Mensik got a second match point thanks to his 18e as. Then, he won the final point on Báez’s serve to close the books.