Tennis
Rublev failed to make it to the fourth round of the Indian Wells tournament
Andrey Rublev / Photo: © Clive Brunskill / Staff / Getty Images Sport / Gettyimages.ru
Russian Andrei Rublev lost to Czech tennis player Jiri Legechka in the third round of the tournament in Indian Wells.
The fifth racket of the tournament, Rublev, lost to his opponent in two sets; the tennis players spent 1 hour and 13 minutes on the court. The Russian made one serve through and made one double fault. Legecka had 9 aces and two double faults.
In the next round, Legechka will meet with the Greek Stefan Tsitsipas (11th seed).
The second racket of the world, Spaniard Carlos Alcaraz, easily dealt with the Canadian Felix Auger-Alassime, the representative of Kazakhstan Alexander Bublik lost to the Australian Alex De Minaur.
WTA 1000. BNP PARIBAS OPEN. Indian Wells (USA). Hard. Prize fund – more than 9.2 million dollars
Third circle
Jiri Legechka (Czech Republic, 32) — Andrey Rublev (Russia, 5) — 6:4, 6:4
Carlos Alcaraz (Spain, 2) – Felix Auger-Alassime (Canada, 31) – 6:2, 6:3
Alex De Minaur (Australia, 10) – Alexander Bublik (Kazakhstan, 20) – 7:5, 6:0
Source: Sportbox
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